If a residential solar photovoltaic system produces 12 MW-hrs in a year with 8 hours of daylight on average, what is its average energy production?

To determine the average energy production of the solar photovoltaic system, we start with the total energy produced over the year, which is given as 12 MW-hours. To find the average power output, we can use the formula that relates energy and power:

[ \text{Power (in kW)} = \frac{\text{Energy (in kW-hrs)}}{\text{Time (in hours)}} ]

In this scenario, the total energy output over the year is 12 MW-hrs. Since 1 MW is equivalent to 1000 kW, we can convert the energy output into kW-hrs:

[ 12 \text{ MW-hrs} = 12,000 \text{ kW-hrs} ]

Next, we need to calculate the total number of daylight hours in a year. With an average of 8 hours of daylight per day, the number of daylight hours in a year can be calculated as:

[ \text{Total daylight hours in a year} = 8 \text{ hours/day} \times 365 \text{ days/year} = 2,920 \text{ hours/year} ]

Now, we can find the average power output over the entire year